Welcome to our latest blog post!
If you’ve ever wondered how to choose the right injection molding machine for your project, understanding clamping force is key.
Today, we’ll break down how to calculate the clamping force required for parts with wall thicknesses both below and above 1.5 mm. Mastering this calculation not only ensures high-quality parts but also helps you make smarter, more efficient equipment choices.
Let’s dive in!
Case 1: part wall thickness below 1.5 mm
Clamping force F [kN] = projected area A [m2] * filling pressure pf [bar] / 100
Filling pressure pf [bar] = Flow factor kf [bar/mm] * wall thickness factor kw [/] * flow length [mm]
Note: 1 bar = 1x10^5 Pa; Pa = N/m^2 = kg/(m x s^2)
Flow factors kf depending which material one is using:
ABS: 2.0
PA: 2.0
PA+GF: 2.4
PBT: 2.0
PBT+GF: 2.3
PC: 2.0
PC+GF: 3.3
PE: 1.8
PESU: 3.7
PMMA: 1.8
POM: 2.4
PP: 1.2
PPO: 1.9
PPO+GF: 3.2
SAN: 1.8
PK (Polyketone): 1.2
Wall thickness factor kw:
0.4 mm: 11.9
0.5 mm: 9.2
0.6 mm: 7.3
0.8 mm: 4.5
1.0 mm: 3.0
1.2 mm: 2.1
1.4 mm: 1.5
1.6 mm: 1.1
Case 2: part wall thickness above 1.5 mm
Clamping force F [kN] = projected area A [m2] * pressure p [bar] / 100
Insert for pressure p:
Thermoplastics = 350 - 400 bar
Thermosets = 450 - 500 bar
Rubbers = 500 bar
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| Figure 1: Overview on clamping force estimation in injection molding. |
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Thanks for reading & #findoutaboutplastics
Greetings,
Herwig
Literature:
[1] https://manuelkuehner.de/wp-content/uploads/2015/04/formelsammlung_polymertechnik_kunststofftechnik_hhn_manuel_kuehner.pdf
[2] https://firstmold.com/de/tips/clamping-force/
[3] https://prototool.com/de/injection-molding-formulas/
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